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  1. CXF
  2. CXF-4039

If the wsdlLocation is not a valid URL, you class.getResource(...)

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Details

    • Improvement
    • Status: Closed
    • Major
    • Resolution: Fixed
    • None
    • 2.4.6, 2.5.2
    • Tooling
    • None
    • Unknown

    Description

      If the wsdlLocation is not a valid URL, we can detect that easily at code generation time with a simple "new URL(wsdlLocation)" and generate more usable code via a class.getResource call instead.

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            dkulp Daniel Kulp
            dkulp Daniel Kulp
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              Updated:
              Resolved: