Add a test for bypassing stuck state-machine procedures

      if (!procedure.isFailed()) {
        if (subprocs != null) {
          if (subprocs.length == 1 && subprocs[0] == procedure) {
            // Procedure returned itself. Quick-shortcut for a state machine-like procedure;
            // i.e. we go around this loop again rather than go back out on the scheduler queue.
            subprocs = null;
            reExecute = true;
            LOG.trace("Short-circuit to next step on pid={}", procedure.getProcId());
          } else {
            // Yield the current procedure, and make the subprocedure runnable
            // subprocs may come back 'null'.
            subprocs = initializeChildren(procStack, procedure, subprocs);
            LOG.info("Initialized subprocedures=" +
              (subprocs == null? null:
                Stream.of(subprocs).map(e -> "{" + e.toString() + "}").
                collect(Collectors.toList()).toString()));
          }
        } else if (procedure.getState() == ProcedureState.WAITING_TIMEOUT) {
          LOG.debug("Added to timeoutExecutor {}", procedure);
          timeoutExecutor.add(procedure);
        } else if (!suspended) {
          // No subtask, so we are done
          procedure.setState(ProcedureState.SUCCESS);
        }
      }

          IdLock.Entry lockEntry = procExecutionLock.getLockEntry(proc.getProcId());
          try {
            executeProcedure(proc);
          } catch (AssertionError e) {
            LOG.info("ASSERT pid=" + proc.getProcId(), e);
            throw e;
          } finally {
            procExecutionLock.releaseLockEntry(lockEntry);

    IdLock.Entry lockEntry = procExecutionLock.tryLockEntry(procedure.getProcId(), lockWait);